해당 데이터로 어떻게 $.each문 돌릴수 있을까요? 채택완료

var arr = [

{"pagelevel":1,"filelist":"qmffodzm12","pagenamelist":"메인페이지"}, 

{"pagelevel":2,"filelist":"8KdLwyqxMU","pagenamelist":"제목없음-N2"}, 

{"pagelevel":3,"filelist":"DU4t36Ou52","pagenamelist":"제목없음-t3"}, 

{"pagelevel":4,"filelist":"ChREtNNtcM","pagenamelist":"제목없음-z4"}, 

{"pagelevel":5,"filelist":"mcQkNoHG8f","pagenamelist":"제목없음-z4"}, 

{"pagelevel":6,"filelist":"jRStL2Pgy3","pagenamelist":"제목없음-d5"}, 

{"pagelevel":7,"filelist":"vjf8emd74y","pagenamelist":"제목없음-P6"}

];

var pagelevel = filelist = pagenamelist = '';

function comma(val) { return val ? val + ',' : val }

for (var i in arr) {

pagelevel = comma(pagelevel) + arr[i].pagelevel; 

filelist = comma(filelist) + arr[i].filelist; 

pagenamelist = comma(pagenamelist) + arr[i].pagenamelist; 

}

console.log(pagelevel, filelist, pagenamelist); 

</script>

var res = JSON.parse(arr), pagelevel = [], filelist = [], pagenamelist = [];for(i=0; i<res.length; i++) {    pagelevel.push(res[i].pagelevel);    filelist.push(res[i].filelist);    pagenamelist.push(res[i].pagenamelist);}alert(pagelevel.join(", "));alert(filelist.join(", "));alert(pagenamelist.join(", "));

alert(pagelevel.join(", "));

얘네는 떼고 쓰셔도 됩니다.

그냥 ,(콤마) 다음에 한 칸 띄우는 게 보기에 좋아서... 

var arr2 = eval('('+arr+')');

$.each(arr2, function(e, obj){

alert(obj.pagelevel);

alert(obj.filelist);

alert(obj.pagenamelist);

});