답변 1개 / 댓글 4개
채택된 답변
+20 포인트
Copy
var from = new Date(2022,4,25);
var to = new Date(2022,4,30);
var num = 200;
for (var day = from; day <= to; day.setDate(day.getDate() + 1)) {
num = num - 1;
}
답변에 대한 댓글 4개
[code]
</head>
<body>
<div id="count"></div>
<script>
function count() {
var from = new Date(2022, 4, 30); // 2022-05-30
var to = new Date(2022, 4, 31); // 2022-05-31
var num = 200000;
for (var day = from; day <= to; day.setDate(day.getDate() + 1)) {
num = num - 1;
}
document.getElementById(count).innerHTML = num + ' 남았습니다.';
}
count();
</script>
</body>
[/code]
or
[code]
<script>
$(function() {
var from = new Date(2022, 4, 30); // 2022-05-30
var to = new Date(2022, 4, 31); // 2022-05-31
var num = 200000;
for (var day = from; day <= to; day.setDate(day.getDate() + 1)) {
num = num - 1;
}
$('#count').html(num + ' 남았습니다.');
});
</script>
</head>
<body>
<div id="count"></div>
[/code]
</head>
<body>
<div id="count"></div>
<script>
function count() {
var from = new Date(2022, 4, 30); // 2022-05-30
var to = new Date(2022, 4, 31); // 2022-05-31
var num = 200000;
for (var day = from; day <= to; day.setDate(day.getDate() + 1)) {
num = num - 1;
}
document.getElementById(count).innerHTML = num + ' 남았습니다.';
}
count();
</script>
</body>
[/code]
or
[code]
<script>
$(function() {
var from = new Date(2022, 4, 30); // 2022-05-30
var to = new Date(2022, 4, 31); // 2022-05-31
var num = 200000;
for (var day = from; day <= to; day.setDate(day.getDate() + 1)) {
num = num - 1;
}
$('#count').html(num + ' 남았습니다.');
});
</script>
</head>
<body>
<div id="count"></div>
[/code]
답변을 작성하려면 로그인이 필요합니다.
<script>
function count()
{
var from = new Date(2022,5,30);
var to = new Date(2022,5,31);
var num = 200000;
for (var day = from; day <= to; day.setDate(day.getDate() + 1)) {
num = num - 1;
}
document.getElementById(count).innerHTML + num + '남았습니다.';
}
</script>
</head>
<body>
<div id="count"></div>
</body>
[/code]
이런식으로 span태그에 뽑아내려고 하는데, 코드상에 문제가 있는건지 담아내질 못하네요 ㅠ