제일첫번째이미지가 있으면 보여주고
없으면 '이미지가 없음'
이라고 표시하고 싶은데 if문을 쓰면 될거같은데요..
변수명을 어떻게 줘야하나요..?

<?
$wr_id=$list[$i][wr_id];
$sql = " select * from $file_table where wr_id = '$wr_id' order by wf_id";
$result = sql_query($sql);

for ($j=0; $row=mysql_fetch_array($result); $j++){
$file_name = get_thumb_filename2($wr_id, $row[wf_id]);
$file = "./data/file/$bo_table/{$file_name}_s.jpg";
$cont=cut_str(get_text($row[wf_cont]),30);
$ss=$list[$i][wr_id];

if ($row[wf_id] < 1 ) {
echo "<tr><td align=center><a href='./?doc=bbs/gnuboard.php&bo_table=$bo_table&wr_id=$ss'><img src='$file' width=40 border=0 alt='$cont'></a> ";
}
}
?>