이미지가 없을때를 정의하고 싶은데 도움좀 주세요~ 채택완료

<SCRIPT LANGUAGE="JavaScript"><!-- image_directory = "";   //배경이미지 경로clear = new Image();  clear.src = image_directory + "./img/blank.gif";<?//파일 뽑기$sql2 = " select bf_file from $g4[board_file_table] where bo_table = '$bo_table' and wr_id = '$wr_id' order by bf_no limit 0, 10 "; $result2 = sql_query($sql2);for ($j=0; $row2 = sql_fetch_array($result2); $j++) {$view_one = "{$g4['path']}/data/file/{$bo_table}/{$row2['bf_file']}";?>view_img<?=$j?> = new Image();view_img<?=$j?>.src = "<?=$g4['path']?>/data/file/<?=$bo_table?>/<?=$row2['bf_file']?>";<? } ?>function bgChange(imgName) {  document.all.view_img.src = eval(imgName + ".src");}//  --></SCRIPT>
 <tr>  <td><table cellpadding="0" cellspacing="0" style="width:100%; border-collapse:collapse; border-spacing:0px;"> <tr>  <td rowspan="13" width="400" style="background:#FFF; padding:15px 10px; text-align:center; border:1px solid #E7E7E7;">
 <div style='width:390px; position:relative; overflow:hidden; padding-bottom:15;'><a href="javascript:void(0);" onClick="View_Open('<?=$view_one?>')"><img src="<?=$view_one?>" name="view_img" border="0" width=390 height=280 style="border-color:#161616;"></a></div>