애왜안될까요;;;
<?
include "dbcon.php";
if($num == "")
{popup_back("잘못된 경로 입니다.");}
include "dbcon.php";
if($num == "")
{popup_back("잘못된 경로 입니다.");}
$sql = "select * from message wgere num = $num";
$res = mysql_query($sql);
show();
mysql_close($con);
//--------------show()함수--------------//
function show()
{
global $res;
//--------------show()함수--------------//
function show()
{
global $res;
$num = mysql_result($res, 0, 'num');
$name = mysql_result($res, 0, 'name');
$email = mysql_result($res, 0, 'email');
$message = mysql_result($res, 0, 'message');
$writedate = mysql_result($res, 0, 'writedate');
$sourceip = mysql_result($res, 0, 'sourceip');
$name = mysql_result($res, 0, 'name');
$email = mysql_result($res, 0, 'email');
$message = mysql_result($res, 0, 'message');
$writedate = mysql_result($res, 0, 'writedate');
$sourceip = mysql_result($res, 0, 'sourceip');
echo("
<table border=1>
<tr>
<td>번호</td>
<td>이름</td>
<td>이메일</td>
<td>작성일</td>
<td>IP</td>
</tr>
<tr>
<td colspan=5>메시지</td>
</tr>
</table>
");
}
//--------------show()함수--------------//
?>
<table border=1>
<tr>
<td>번호</td>
<td>이름</td>
<td>이메일</td>
<td>작성일</td>
<td>IP</td>
</tr>
<tr>
<td colspan=5>메시지</td>
</tr>
</table>
");
}
//--------------show()함수--------------//
?>
이렇게 했거든여
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 18
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 19
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 20
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 21
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 22
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 23
이런 에러가나네요
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 19
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 20
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 21
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 22
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in C:\AutoSet6\public_html\view.php on line 23
이런 에러가나네요
mysql연결은 다되있고 확인까지 했는데 저러네용;;
|
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