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from gekko import GEKKO
import numpy as np
import matplotlib.pyplot as plt

m = GEKKO(remote=True)
m.options.SOLVER = 1
 

hour = 24                            
Num_User = 3                      
Num_ESS  = 1

p_i = m.Array(m.Var,(hour, Num_User))   

alpha = np.array([0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5,0.5])
a = alpha

omega = np.array([4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4,4])
w = omega

pi_t = np.array([70,70,70,70,70,70,70,70,70,121.2,143.7,143.7,121.2,143.7,143.7,143.7,143.7,121.2,121.2,121.2,121.2,121.2,121.2,70])
p_t = pi_t

U_EC = bin
C = U_EC

U_ED = bin
D = U_ED

x_t = m.Array(m.Var,(hour, Num_User))
SOC_t = m.Array(m.Var,(hour, Num_User))
ESS_c = m.Array(m.Var,(hour, Num_User))
ESS_d = m.Array(m.Var,(hour, Num_User))

for tt in range(0,hour):
    p_i[tt,0].lower =     0; p_i[tt,1].lower =  0; p_i[tt,2].lower =     0; x_t[tt,0].lower = 0
    p_i[tt,0].upper = 21.09; p_i[tt,0].upper = 20; p_i[tt,0].upper = 21.84; x_t[tt,0].upper = 2

for tt in range(0,hour):
    x_t[tt,0].lower = 0; x_t[tt,1].lower = 0; x_t[tt,2].lower = 0
    x_t[tt,0].upper = 8; x_t[tt,1].upper = 8; x_t[tt,0].upper = 8

for tt in range(0,hour):
    SOC_t[tt,0].lower =  0; ESS_c[tt,0].lower =   0; ESS_d[tt,0].lower =   0
    SOC_t[tt,0].upper = 20; ESS_c[tt,0].upper = 100; ESS_d[tt,0].upper = 100 

eq_U = np.zeros((hour, 3))
eq_U = list(eq_U)

for tt in range(0, hour):
    for i in range(0,Num_User):
        if x_t[tt,i] >= w[tt,i]/a[tt,i]:
            eq_U[tt] = w[i,tt]/a[i,tt]
        else:
            eq_U[tt] = w[i,tt]*x_t[i,tt]-(a[i,tt]/2)*x_t[i,tt]**2

---------------------------------------------------------------------------

IndexError Traceback (most recent call last)

Cell In [10], line 8

6 for tt in range(0, hour):

7 for i in range(0,Num_User):

----> 8 if x_t[tt,i] >= w[tt,i]/a[tt,i]:

9 eq_U[tt] = w[i,tt]/a[i,tt]

10 else:

IndexError: too many indices for array: array is 1-dimensional, but 2 were indexed