create_function를 PHP7.2 형식으로 전환하려면?
본문
$callback = create_function('$arg', 'return mw_soundcloud($arg[1], $arg[2]);');
$str = preg_replace('/\[soundcloud url="([^"]+)".*params="([^"]+)".*\]/i', $callback, $str);
.......
function mw_soundcloud($src, $param)
{
$src = str_replace('"', '', $src);
$src = str_replace('"', '', $src);
$param = str_replace('"', '', $param);
$param = str_replace('"', '', $param);
$s = sprintf('<iframe width="100%%" height="162" scrolling="no" frameborder="no" src="https://w.soundcloud.com/player/?url=%s&%s"></iframe>', urlencode($src), urlencode($param));
return $s;
}
위 코드 첫 라인에서 아래와 같은 에러를 뿜는데...
Deprecated: Function create_function() is deprecated in C:\AutoSet10\public_html\mw7\skin\board\miwit\mw.lib\mw.function.lib.php on line 1511
어떤 식으로 변경해줘야 에러를 해결 가능할까요?
※ 단순히 안 보이게 하는 거 말구..^^
PS.
아래처럼 바꿔봤는데도 에러가 나네요.
$callback = function($arg) use($src, $param) {
global $src, $param;
return mw_soundcloud($arg[1], $arg[2]);
};
!-->
답변 2
function mw_soundcloud($matches)
{
return sprintf('<iframe width="100%%" height="162" scrolling="no" frameborder="no" src="https://w.soundcloud.com/player/?url=%s&%s"></iframe>', urlencode($matches[1]), urlencode($matches[2]));
}
$str = preg_replace_callback('/\[soundcloud url="([^"]+)".*params="([^"]+)".*\]/i', 'mw_soundcloud', $str);
<?php
function mw_soundcloud($src, $param)
{
$src = str_replace('"', '', $src);
$src = str_replace('"', '', $src);
$param = str_replace('"', '', $param);
$param = str_replace('"', '', $param);
$s = sprintf('<iframe width="100%%" height="162" scrolling="no" frameborder="no" src="https://w.soundcloud.com/player/?url=%s&%s"></iframe>', urlencode($src), urlencode($param));
return $s;
}
// < 7.2
//$callback = create_function('$arg', 'return mw_soundcloud($arg[1], $arg[2]);');
// >= 7.2
$callback = function ($arg) { return mw_soundcloud($arg[1], $arg[2]); };
$str = 'zzz[soundcloud url="http://www.soundcloud.com/a/1.mp3" params="a=1&b=2"z]zzz';
$str = preg_replace_callback('/\[soundcloud url="([^"]+)".*params="([^"]+)".*\]/i', $callback, $str);
echo $str;
?>